What is the integral of (x+1)/(x^2+2x+3) ?

The integral of (x+1)/(x^2+2x+3) is 1/2 ln|x^2+2x+3|+C

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integral of (x+1)/(x^2+2x+3)

\int \frac{x + 1}{x ^{2} + 2 x + 3} d x

\frac{1}{2} ln x^{2} + 2 x + 3 + C

Solution steps

\int \frac{x + 1}{x ^{2} + 2 x + 3} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = x^{2} + 2 x + 3

= \frac{1}{2} ln x^{2} + 2 x + 3

Add a constant to the solution

= \frac{1}{2} ln x^{2} + 2 x + 3 + C

\int \frac{e ^{3 x}}{9 + 4 e ^{6 x}} d x

\frac{2}{s ^{5}}

x \to 0 lim (\frac{( 2 + x ) ^{3} - 8}{x})

\int - 4 sin (4 x) d x

\frac{d}{d x} (cos (e^{- x}))

What is the integral of (x+1)/(x^2+2x+3) ?
The integral of (x+1)/(x^2+2x+3) is 1/2 ln|x^2+2x+3|+C