What is the limit as x approaches 4 of \sqrt[3]{3-x} ?

The limit as x approaches 4 of \sqrt[3]{3-x} is cube root of-1

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limit as x approaches 4 of \sqrt[3]{3-x}

x \to 4 lim (3 3 - x)

3 - 1

Solution steps

x \to 4 lim (3 3 - x)

Plug in the value

x = 4

= 3 3 - 4

Simplify

= 3 - 1

x \to 0 lim (\frac{1}{x + 4} - \frac{1}{4})

x \to 7 lim (g (x))

x \to 2 lim (\frac{x ^{2} - 9}{x + 3})

x \to 0 lim (\frac{2 x + sin ( x )}{x})

x \to - 1 lim (- 4 x)

What is the limit as x approaches 4 of \sqrt[3]{3-x} ?
The limit as x approaches 4 of \sqrt[3]{3-x} is cube root of-1