What is the solution for (dy)/(dt)=\sqrt[3]{tan(3t)} ?

The solution for (dy)/(dt)=\sqrt[3]{tan(3t)} is y=integral of \sqrt[3]{tan(3t)}

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(dy)/(dt)=\sqrt[3]{tan(3t)}

Solution steps

Substitute

\frac{d y}{d t}

with

y^{'} (t)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

2 y^{2} = \frac{d y}{d x}

\int_{1}^{e} \frac{( x ^{2} - 1 )}{x} d x

\frac{d}{d t} (e^{- 2 t})

\frac{d}{d x} (x^{4} + \frac{1}{32 x ^{2}})

\frac{\partial}{\partial x} (x^{0.5} \cdot y^{0.5})

What is the solution for (dy)/(dt)=\sqrt[3]{tan(3t)} ?
The solution for (dy)/(dt)=\sqrt[3]{tan(3t)} is y=integral of \sqrt[3]{tan(3t)}