What is the limit as x approaches pi of cos(9x) ?

The limit as x approaches pi of cos(9x) is -1

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limit as x approaches pi of cos(9x)

x \to π lim (cos (9 x))

- 1

Solution steps

x \to π lim (cos (9 x))

Plug in the value

x = π

= cos (9 π)

Simplify

cos (9 π) : - 1

= - 1

x \to - π lim (ln (sin (x)))

j \to 0 lim (\frac{( 3 - j ) ^{2} - 9}{j})

x \to 0 lim (x (x - 2))

x \to 3.5 lim (\frac{( x - 2 )}{x})

x \to 0 lim ([x^{2} + 4 x + 4])

What is the limit as x approaches pi of cos(9x) ?
The limit as x approaches pi of cos(9x) is -1