What is the limit as z approaches 1+i of 3z^2+z-5 ?

The limit as z approaches 1+i of 3z^2+z-5 is 3i^2+7i-1

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limit as z approaches 1+i of 3z^2+z-5

z \to 1 + i lim (3 z^{2} + z - 5)

3 i^{2} + 7 i - 1

Solution steps

z \to 1 + i lim (3 z^{2} + z - 5)

Plug in the value

z = 1 + i

= 3 (1 + i)^{2} + 1 + i - 5

Simplify

3 (1 + i)^{2} + 1 + i - 5 : 3 i^{2} + 7 i - 1

= 3 i^{2} + 7 i - 1

x \to 0 + lim (x^{\frac{1}{0}})

t \to 1 lim (sin (- 4 π t))

x \to π lim (sin (2 x))

x \to 2 - lim (ln (x^{2} - 4))

x \to 0 + lim (\frac{1}{x ^{2}} - x^{2})

What is the limit as z approaches 1+i of 3z^2+z-5 ?
The limit as z approaches 1+i of 3z^2+z-5 is 3i^2+7i-1