What is the limit as x approaches 0+of 1/(x^2)-x^2 ?

The limit as x approaches 0+of 1/(x^2)-x^2 is infinity

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limit as x approaches 0+of 1/(x^2)-x^2

x \to 0 + lim (\frac{1}{x ^{2}} - x^{2})

\infty

Solution steps

x \to 0 + lim (\frac{1}{x ^{2}} - x^{2})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (\frac{1}{x ^{2}}) - x \to 0 + lim (x^{2})

x \to 0 + lim (\frac{1}{x ^{2}}) = \infty

x \to 0 + lim (x^{2}) = 0

= \infty - 0

Apply Infinity Property:

\infty - c = \infty

= \infty

x \to 4 lim (5 x^{2} - 9 x - 8)

x \to - 2 + lim (4 - x^{2})

x \to - \infty lim (6 \cdot (x))

x \to \infty lim ((1 - tan (2 x))^{3 c s c (4 x)})

x \to 0 lim ((2^{x} + x)^{\frac{9}{x}})

What is the limit as x approaches 0+of 1/(x^2)-x^2 ?
The limit as x approaches 0+of 1/(x^2)-x^2 is infinity