What is the limit as x approaches-1 of 1/(ln(x)) ?

The limit as x approaches-1 of 1/(ln(x)) is Does not exist

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limit as x approaches-1 of 1/(ln(x))

x \to - 1 lim (\frac{1}{ln ( x )})

Does not exist

Solution steps

x \to - 1 lim (\frac{1}{ln ( x )})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 1 - lim (\frac{1}{ln ( x )}) =

Does not exist

x \to - 1 + lim (\frac{1}{ln ( x )}) =

Does not exist

= Does not exist

x \to 2 lim (\frac{\frac{8}{x} - 4}{x - 2})

x \to 1 lim (x^{2} - 3 x)

x \to 0 lim (x^{π x})

x \to \infty lim (x 6^{x} + 7^{x} + 8^{x})

x \to 1 lim (x^{2} - 17)

What is the limit as x approaches-1 of 1/(ln(x)) ?
The limit as x approaches-1 of 1/(ln(x)) is Does not exist