What is the solution for f^'(x)=sin(x^2) ?

The solution for f^'(x)=sin(x^2) is f(x)=sqrt(pi/2)\S(sqrt(2/pi)x)+c_{1}

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f^'(x)=sin(x^2)

f^{^{'}} (x) = sin (x^{2})

f (x) = \frac{π}{2} § (\frac{2}{π} x) + c_{1}

Solution steps

f^{'} (x) = sin (x^{2})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int sin (x^{2}) d x

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x) + c_{1}

f (x) = \frac{π}{2} § (\frac{2}{π} x) + c_{1}

\frac{d}{d x} ((sin (x))^{l n (x)})

\frac{\partial}{\partial x} (x^{2} y + 5 y^{3})

\frac{d x}{d t} = 3 t^{2} (x^{2} + 4)

\frac{\partial}{\partial x} (9 \frac{x yz}{x + y + z})

\int \frac{3}{x + 3} d x

What is the solution for f^'(x)=sin(x^2) ?
The solution for f^'(x)=sin(x^2) is f(x)=sqrt(pi/2)\S(sqrt(2/pi)x)+c_{1}