What is (\partial)/(\partial y)(2x+y^2) ?

The answer to (\partial)/(\partial y)(2x+y^2) is 2y

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(\partial)/(\partial y)(2x+y^2)

\frac{\partial}{\partial y} (2 x + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (2 x + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

f (x) = x^{3}, 0, 4

y^{^{'}} - 3 y = - 6 y^{3}

\int_{0}^{1} \frac{4}{1 - x ^{2}} d x

x \to 0 lim (\frac{x}{x ^{2} - 9 x})

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + e ^{- x}})

What is (\partial)/(\partial y)(2x+y^2) ?
The answer to (\partial)/(\partial y)(2x+y^2) is 2y