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Popular >

integral from 1 to 2 of (1+2y)

Solution

\int_{1}^{2} (1 + 2 y) d y

Solution

4

Solution steps

\int_{1}^{2} 1 + 2 y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 1 d y + \int_{1}^{2} 2 y d y

\int_{1}^{2} 1 d y = 1

\int_{1}^{2} 2 y d y = 3

= 1 + 3

Simplify

= 4

Popular Examples

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x \to 0 lim (3 x^{2})

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\frac{d}{d x} (3 x^{2} - 2 y^{2})

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\int sin (u) cos^{2} (u) d u

integral from 1 to 2 of x^3+x^2-1

\int_{1}^{2} x^{3} + x^{2} - 1 d x

integral from 0 to 5 of x^3e^x

\int_{0}^{5} x^{3} e^{x} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (1+2y) ?
The integral from 1 to 2 of (1+2y) is 4