What is the tangent of f(x)=4-x^2,\at x=-4 ?

The tangent of f(x)=4-x^2,\at x=-4 is y=8x+20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=4-x^2,\at x=-4

tangent of

f (x) = 4 - x^{2}, at x = - 4

y = 8 x + 20

Solution steps

Find the tangent point:

(- 4, - 12)

Find the slope of

f (x) = 4 - x^{2} : \frac{df ( x )}{d x} = - 2 x

Compute the slope of

f (x) = 4 - x^{2}

x = - 4 : m = 8

Find the line with slope m=

8

and passing through

(- 4, - 12) : y = 8 x + 20

y = 8 x + 20

\int \frac{10}{x} + 10 x d x

x \to - 2 + lim (\frac{∣ x + 2 ∣}{x + 2})

\int \frac{x + 11}{x ^{2} + 16 x + 68} d x

x \to 1 lim (x^{2} + 3 x)

x \to 1 lim (\frac{x ^{3} - x ^{2} - 4 x + 4}{x ^{3} + 6 x ^{2} + 5 x - 12})

What is the tangent of f(x)=4-x^2,\at x=-4 ?
The tangent of f(x)=4-x^2,\at x=-4 is y=8x+20