What is the limit as x approaches 0 of 1/((x-3)^2) ?

The limit as x approaches 0 of 1/((x-3)^2) is 1/9

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limit as x approaches 0 of 1/((x-3)^2)

x \to 0 lim (\frac{1}{( x - 3 ) ^{2}})

\frac{1}{9}

Decimal

0.11111 \dots

Solution steps

x \to 0 lim (\frac{1}{( x - 3 ) ^{2}})

Plug in the value

x = 0

= \frac{1}{( 0 - 3 ) ^{2}}

Simplify

\frac{1}{( 0 - 3 ) ^{2}} : \frac{1}{9}

= \frac{1}{9}

x \to 1 lim (\frac{x ^{34} - 1}{x ^{27} + 1})

x \to π - lim (- ln (1 + cos (x)))

x \to 0 lim (x^{2} \cdot ln (x^{2}))

x \to \infty lim (- x^{5})

x \to - 2 lim (x + 7)

What is the limit as x approaches 0 of 1/((x-3)^2) ?
The limit as x approaches 0 of 1/((x-3)^2) is 1/9