What is the limit as x approaches 3 of x^2-8x+16 ?

The limit as x approaches 3 of x^2-8x+16 is 1

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limit as x approaches 3 of x^2-8x+16

x \to 3 lim (x^{2} - 8 x + 16)

1

Solution steps

x \to 3 lim (x^{2} - 8 x + 16)

Plug in the value

x = 3

= 3^{2} - 8 \cdot 3 + 16

Simplify

= 1

x \to 0 lim (\frac{sin ( 8 x ) - 2}{x})

x \to 0 lim (ln (3 x))

x \to 0 lim (f (x) (1 - x^{2}))

x \to 9 lim (x + 3)

x \to - 0 lim (\frac{sin ( 4 x )}{x})

What is the limit as x approaches 3 of x^2-8x+16 ?
The limit as x approaches 3 of x^2-8x+16 is 1