What is the derivative of (x^2-4)/(sqrt(x)) ?

The derivative of (x^2-4)/(sqrt(x)) is (3x^2+4)/(2xsqrt(x))

What is the first derivative of (x^2-4)/(sqrt(x)) ?

The first derivative of (x^2-4)/(sqrt(x)) is (3x^2+4)/(2xsqrt(x))

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derivative of

\frac{x ^{2} - 4}{x}

\frac{3 x ^{2} + 4}{2 x x}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 4}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 4 ) x - \frac{d}{d x} ( x ) ( x ^{2} - 4 )}{( x ) ^{2}}

\frac{d}{d x} (x^{2} - 4) = 2 x

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{2 x x - \frac{1}{2 x} ( x ^{2} - 4 )}{( x ) ^{2}}

Simplify

\frac{2 x x - \frac{1}{2 x} ( x ^{2} - 4 )}{( x ) ^{2}} : \frac{3 x ^{2} + 4}{2 x x}

= \frac{3 x ^{2} + 4}{2 x x}

8 sin (x)

x y^{^{'}} + 2 y = 4 e^{x}

\int_{- 1}^{0} (x - 2) d x

x \to - \infty lim (\frac{x + 3 e ^{2 x}}{x + e ^{2 x}})

x, x = 8 - \frac{1}{4} y^{2}

What is the derivative of (x^2-4)/(sqrt(x)) ?
The derivative of (x^2-4)/(sqrt(x)) is (3x^2+4)/(2xsqrt(x))
What is the first derivative of (x^2-4)/(sqrt(x)) ?
The first derivative of (x^2-4)/(sqrt(x)) is (3x^2+4)/(2xsqrt(x))