What is the derivative of sqrt(19x^2+9) ?

The derivative of sqrt(19x^2+9) is (19x)/(sqrt(19x^2+9))

What is the first derivative of sqrt(19x^2+9) ?

The first derivative of sqrt(19x^2+9) is (19x)/(sqrt(19x^2+9))

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\frac{d}{d x} (19 x^{2} + 9)

\frac{19 x}{19 x ^{2} + 9}

Solution steps

\frac{d}{d x} (19 x^{2} + 9)

Apply the chain rule:

\frac{1}{2 19 x ^{2} + 9} \frac{d}{d x} (19 x^{2} + 9)

= \frac{1}{2 19 x ^{2} + 9} \frac{d}{d x} (19 x^{2} + 9)

\frac{d}{d x} (19 x^{2} + 9) = 38 x

= \frac{1}{2 19 x ^{2} + 9} \cdot 38 x

Simplify

\frac{1}{2 19 x ^{2} + 9} \cdot 38 x : \frac{19 x}{19 x ^{2} + 9}

= \frac{19 x}{19 x ^{2} + 9}

\int x + 4 d x

x \to 1 lim (tan (\frac{π x}{2}))

y^{^{'}} = \frac{( x y )}{2}

x \to 1 + lim (\frac{1}{x - 1} - \frac{1}{ln ( x )})

\int \frac{( e ^{6 x} )}{e ^{6 x} + 1} d x

What is the derivative of sqrt(19x^2+9) ?
The derivative of sqrt(19x^2+9) is (19x)/(sqrt(19x^2+9))
What is the first derivative of sqrt(19x^2+9) ?
The first derivative of sqrt(19x^2+9) is (19x)/(sqrt(19x^2+9))