What is (\partial ^2)/(\partial r\partial θ)(r(θ)*cos(θ)) ?

The answer to (\partial ^2)/(\partial r\partial θ)(r(θ)*cos(θ)) is cos(θ)-θsin(θ)

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(\partial ^2)/(\partial r\partial θ)(r(θ)*cos(θ))

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) \cdot cos (θ))

cos (θ) - θ sin (θ)

Solution steps

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) cos (θ))

\frac{\partial}{\partial r} (r θ cos (θ)) = θ cos (θ)

= \frac{\partial}{\partial θ} (θ cos (θ))

\frac{\partial}{\partial θ} (θ cos (θ)) = cos (θ) - θ sin (θ)

= cos (θ) - θ sin (θ)

x = 6 y^{2}, x + y = 5

\frac{\partial}{\partial x} (\frac{v}{6 + uv w})

\frac{d y}{d t} = (t y)^{2}

(x^{2} - 2 x + 1)^{^{'}}

\frac{d}{d x} (\frac{2 x + 3}{3 x - 2})

What is (\partial ^2)/(\partial r\partial θ)(r(θ)*cos(θ)) ?
The answer to (\partial ^2)/(\partial r\partial θ)(r(θ)*cos(θ)) is cos(θ)-θsin(θ)