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Popular >

(x^2-2x+1)^'

Solution

(x^{2} - 2 x + 1)^{^{'}}

Solution

2 x - 2

Solution steps

(x^{2} - 2 x + 1)^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (x^{2})^{^{'}} - (2 x)^{^{'}} + 1^{^{'}}

(x^{2})^{'} = 2 x

(2 x)^{'} = 2

1^{'} = 0

= 2 x - 2 + 0

Simplify

= 2 x - 2

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Frequently Asked Questions (FAQ)

What is the (x^2-2x+1)^' ?
The (x^2-2x+1)^' is 2x-2
What is the first (x^2-2x+1)^' ?
The first (x^2-2x+1)^' is 2x-2