What is the d/(dθ)(10sin(θ)) ?

The d/(dθ)(10sin(θ)) is 10cos(θ)

What is the first d/(dθ)(10sin(θ)) ?

The first d/(dθ)(10sin(θ)) is 10cos(θ)

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\frac{d}{d θ} (10 sin (θ))

10 cos (θ)

Solution steps

\frac{d}{d θ} (10 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 10 cos (θ)

\frac{d}{d x} (ln (\frac{3 e ^{x}}{2 x ^{2}}))

x \to \infty lim (e^{x l n (\frac{3}{5})})

\int \frac{3 + x ^{2}}{1 + x ^{2}} d x

\frac{\partial}{\partial y} (x + y)

x, 100