What is the limit as x approaches infinity of e^{xln(3/5)} ?

The limit as x approaches infinity of e^{xln(3/5)} is 0

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limit as x approaches infinity of e^{xln(3/5)}

x \to \infty lim (e^{x l n (\frac{3}{5})})

0

Solution steps

x \to \infty lim (e^{x l n (\frac{3}{5})})

Simplify

e^{x l n (\frac{3}{5})} : (\frac{3}{5})^{x}

= x \to \infty lim ((\frac{3}{5})^{x})

Apply the common limit:

x \to \infty lim (a^{x}) = 0, 0 < a < 1

= 0

\int \frac{3 + x ^{2}}{1 + x ^{2}} d x

\frac{\partial}{\partial y} (x + y)

x, 100

\frac{d y}{d x} = x + 2 y, y (0) = 7

f (x) = 2 - 7 x^{2}, at x = 4

What is the limit as x approaches infinity of e^{xln(3/5)} ?
The limit as x approaches infinity of e^{xln(3/5)} is 0