What is the solution for (dy)/(dx)=x+2y,y(0)=7 ?

The solution for (dy)/(dx)=x+2y,y(0)=7 is y=-(2x+1)/4+29/4 e^{2x}

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(dy)/(dx)=x+2y,y(0)=7

\frac{d y}{d x} = x + 2 y, y (0) = 7

y = - \frac{2 x + 1}{4} + \frac{29}{4} e^{2 x}

Solution steps

\frac{d y}{d x} = x + 2 y

Solve linear ODE:

y = - \frac{2 x + 1}{4} + \frac{29}{4} e^{2 x}

y = - \frac{2 x + 1}{4} + \frac{29}{4} e^{2 x}

f (x) = 2 - 7 x^{2}, at x = 4

\frac{d}{d x} (e^{x} \cdot cos (y))

\int y e^{y} d y

x \to \infty lim (5 x + 4)

\frac{\partial}{\partial x} (x sin (7 x^{2} y))

What is the solution for (dy)/(dx)=x+2y,y(0)=7 ?
The solution for (dy)/(dx)=x+2y,y(0)=7 is y=-(2x+1)/4+29/4 e^{2x}