What is the derivative of 2e^{-4x} ?

The derivative of 2e^{-4x} is -8e^{-4x}

What is the first derivative of 2e^{-4x} ?

The first derivative of 2e^{-4x} is -8e^{-4x}

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\frac{d}{d x} (2 e^{- 4 x})

- 8 e^{- 4 x}

Solution steps

\frac{d}{d x} (2 e^{- 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{d}{d x} (- 4 x)

= e^{- 4 x} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= 2 e^{- 4 x} (- 4)

Simplify

= - 8 e^{- 4 x}

\int \frac{1}{( 9 x ^{2} + 1 ) ^{\frac{5}{2}}} d x

x = - 1, x = y^{3}, [0, 1]

\frac{d}{d x} (8 + cot^{2} (x))

x \to 2 lim (3 x^{3} + x^{2} - 8)

f (x) = 6 x^{9} e^{x}

What is the derivative of 2e^{-4x} ?
The derivative of 2e^{-4x} is -8e^{-4x}
What is the first derivative of 2e^{-4x} ?
The first derivative of 2e^{-4x} is -8e^{-4x}