What is the limit as x approaches-1-of (2-x)/(x+1) ?

The limit as x approaches-1-of (2-x)/(x+1) is -infinity

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limit as x approaches-1-of (2-x)/(x+1)

x \to - 1 - lim (\frac{2 - x}{x + 1})

- \infty

Solution steps

x \to - 1 - lim (\frac{2 - x}{x + 1})

\frac{2 - x}{x + 1} = (2 - x) \frac{1}{x + 1}

= x \to - 1 - lim ((2 - x) \frac{1}{x + 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to - 1 - lim (2 - x) \cdot x \to - 1 - lim (\frac{1}{x + 1})

x \to - 1 - lim (2 - x) = 3

x \to - 1 - lim (\frac{1}{x + 1}) = - \infty

= 3 (- \infty)

Apply Infinity Property:

c \cdot (- \infty) = - \infty

= - \infty

x \to 0 lim (- (2^{\frac{1}{x}}))

x \to 3 lim (\frac{4 - x ^{2}}{x + 3})

x \to 6 lim (\frac{x ^{2} - 4}{x - 6})

h \to 0 lim (\frac{( h - 2 ) ^{3} + 8}{h})

t \to 1 lim (sin (2 t))

What is the limit as x approaches-1-of (2-x)/(x+1) ?
The limit as x approaches-1-of (2-x)/(x+1) is -infinity