What is the d/(dA)(-cos(2)(A)-sin(2)(A)) ?

The d/(dA)(-cos(2)(A)-sin(2)(A)) is -cos(2)-sin(2)

What is the first d/(dA)(-cos(2)(A)-sin(2)(A)) ?

The first d/(dA)(-cos(2)(A)-sin(2)(A)) is -cos(2)-sin(2)

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\frac{d}{d A} (- cos (2) (A) - sin (2) (A))

- cos (2) - sin (2)

Solution steps

\frac{d}{d A} (- cos (2) (A) - sin (2) (A))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d A} (cos (2) A) - \frac{d}{d A} (sin (2) A)

\frac{d}{d A} (cos (2) A) = cos (2)

\frac{d}{d A} (sin (2) A) = sin (2)

= - cos (2) - sin (2)

\int \frac{1}{x + y} d x

f (x) = \frac{2 x ^{2} + 4 x + 2}{x}

\frac{\partial}{\partial x} (y + 3 x y^{2} - 18)

f (x) = sin (x), at x = \frac{7 π}{6}

x \to 2 lim (\frac{8 - x ^{3}}{x ^{2} - 2 x})

What is the d/(dA)(-cos(2)(A)-sin(2)(A)) ?
The d/(dA)(-cos(2)(A)-sin(2)(A)) is -cos(2)-sin(2)
What is the first d/(dA)(-cos(2)(A)-sin(2)(A)) ?
The first d/(dA)(-cos(2)(A)-sin(2)(A)) is -cos(2)-sin(2)