What is (\partial)/(\partial x)(y+3xy^2-18) ?

The answer to (\partial)/(\partial x)(y+3xy^2-18) is 3y^2

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(\partial)/(\partial x)(y+3xy^2-18)

\frac{\partial}{\partial x} (y + 3 x y^{2} - 18)

3 y^{2}

Solution steps

\frac{\partial}{\partial x} (y + 3 x y^{2} - 18)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (3 x y^{2}) - \frac{\partial}{\partial x} (18)

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (3 x y^{2}) = 3 y^{2}

\frac{\partial}{\partial x} (18) = 0

= 0 + 3 y^{2} - 0

Simplify

= 3 y^{2}

f (x) = sin (x), at x = \frac{7 π}{6}

x \to 2 lim (\frac{8 - x ^{3}}{x ^{2} - 2 x})

\int \frac{x + x}{x ^{2}} d x

\frac{d}{d x} (7 sin (x) - 7 x cos (x))

What is (\partial)/(\partial x)(y+3xy^2-18) ?
The answer to (\partial)/(\partial x)(y+3xy^2-18) is 3y^2