What is the integral of (x+sqrt(x))/(x^2) ?

The integral of (x+sqrt(x))/(x^2) is ln|x|-2/(sqrt(x))+C

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integral of (x+sqrt(x))/(x^2)

\int \frac{x + x}{x ^{2}} d x

ln ∣ x ∣ - \frac{2}{x} + C

Solution steps

\int \frac{x + x}{x ^{2}} d x

Expand

\frac{x + x}{x ^{2}} : \frac{1}{x} + \frac{1}{x ^{\frac{3}{2}}}

= \int \frac{1}{x} + \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int \frac{1}{x ^{\frac{3}{2}}} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{1}{x ^{\frac{3}{2}}} d x = - \frac{2}{x}

= ln ∣ x ∣ - \frac{2}{x}

Add a constant to the solution

= ln ∣ x ∣ - \frac{2}{x} + C

\frac{d}{d x} (7 sin (x) - 7 x cos (x))

\int_{0}^{π} 2 sin (x) d x

\frac{d}{d θ} (- 8 sin (θ))

\frac{2}{s + 10.04}

x \to - \infty lim (3 - 4 x^{2})

What is the integral of (x+sqrt(x))/(x^2) ?
The integral of (x+sqrt(x))/(x^2) is ln|x|-2/(sqrt(x))+C