What is the derivative of x^2-3x+7 ?

The derivative of x^2-3x+7 is 2x-3

What is the first derivative of x^2-3x+7 ?

The first derivative of x^2-3x+7 is 2x-3

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derivative of

x^{2} - 3 x + 7

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (7) = 0

= 2 x - 3 + 0

Simplify

= 2 x - 3

f (x) = x^{2} + 4, g (x) = - x^{2} - 1, [- 2, 3]

x \to 2 lim (\frac{x - 3}{x + 5})

y^{^{''}} - 2 y^{^{'}} + 4 y = 0, y^{^{'}} (0) = 2, y (0) = 1

\frac{\partial}{\partial x} (- 2)

\frac{\partial}{\partial x} (y \cdot cos (y - 2 x))

What is the derivative of x^2-3x+7 ?
The derivative of x^2-3x+7 is 2x-3
What is the first derivative of x^2-3x+7 ?
The first derivative of x^2-3x+7 is 2x-3