What is (\partial)/(\partial x)(y*cos(y-2x)) ?

The answer to (\partial)/(\partial x)(y*cos(y-2x)) is 2ysin(y-2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(y*cos(y-2x))

\frac{\partial}{\partial x} (y \cdot cos (y - 2 x))

2 y sin (y - 2 x)

Solution steps

\frac{\partial}{\partial x} (y cos (y - 2 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (cos (y - 2 x))

Apply the chain rule:

- sin (y - 2 x) \frac{\partial}{\partial x} (y - 2 x)

= - sin (y - 2 x) \frac{\partial}{\partial x} (y - 2 x)

\frac{\partial}{\partial x} (y - 2 x) = - 2

= y (- sin (y - 2 x) (- 2))

Simplify

= 2 y sin (y - 2 x)

n = 0 \sum \infty 9 (\frac{x - 3}{4})^{n}

\int (e^{3 x} sin (2 x)) d x

y^{^{''}} - 3 y^{^{'}} = 8 x

x \to 4 + lim (\frac{x}{x - 4})

\frac{1}{3 s + 2}

What is (\partial)/(\partial x)(y*cos(y-2x)) ?
The answer to (\partial)/(\partial x)(y*cos(y-2x)) is 2ysin(y-2x)