What is inverse oflaplace 1/(3s+2) ?

The answer to inverse oflaplace 1/(3s+2) is 1/3 e^{-(2t)/3}

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inverse oflaplace 1/(3s+2)

inverse laplace

\frac{1}{3 s + 2}

\frac{1}{3} e^{- \frac{2 t}{3}}

Solution steps

L^{- 1} {\frac{1}{3 s + 2}}

= L^{- 1} {\frac{1}{3} \cdot \frac{1}{s + \frac{2}{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{3} L^{- 1} {\frac{1}{s + \frac{2}{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + \frac{2}{3}}} = e^{- \frac{2 t}{3}}

= \frac{1}{3} e^{- \frac{2 t}{3}}

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{1 + x})

\frac{5 x}{x + 2}

7 x^{3}

\frac{\partial}{\partial x} (cos (x) + sin (y))

\int x^{6} ln (2 x) d x

What is inverse oflaplace 1/(3s+2) ?
The answer to inverse oflaplace 1/(3s+2) is 1/3 e^{-(2t)/3}