What is the integral from 0 to 1 of integral from 0 to x of (6/7 (x^2+x*y/2)) ?

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integral from 0 to 1 of integral from 0 to x of (6/7 (x^2+x*y/2))

\int_{0}^{1} \int_{0}^{x} (\frac{6}{7} (x^{2} + x \cdot \frac{y}{2})) d y d x

\frac{15}{56}

Decimal Notation

0.26785 \dots

Solution steps

\int_{0}^{1} \int_{0}^{x} (\frac{6}{7} (x^{2} + x \frac{y}{2})) d y d x

\int_{0}^{x} (\frac{6}{7} (x^{2} + x \frac{y}{2})) d y = \frac{15 x ^{3}}{14}

= \int_{0}^{1} (\frac{15 x ^{3}}{14}) d x

\int_{0}^{1} (\frac{15 x ^{3}}{14}) d x = \frac{15}{56}

= \frac{15}{56}

y = \frac{t}{( t - 7 ) ^{2}}

x \to \infty lim (ln (9 x) - ln (x + 7))

\int \frac{1}{ln ( x ) x} d x

\int \frac{ln ( x )}{2 x} d x

f (x) = (1 n (x^{3}))

What is the integral from 0 to 1 of integral from 0 to x of (6/7 (x^2+x*y/2)) ?
The integral from 0 to 1 of integral from 0 to x of (6/7 (x^2+x*y/2)) is 15/56