What is the derivative of f(x)=(1n(x^3)) ?

The derivative of f(x)=(1n(x^3)) is 3nx^2

What is the first derivative of f(x)=(1n(x^3)) ?

The first derivative of f(x)=(1n(x^3)) is 3nx^2

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derivative of

f (x) = (1 n (x^{3}))

3 n x^{2}

Solution steps

\frac{d}{d x} (1 \cdot n x^{3})

Simplify

1 \cdot n x^{3} : n x^{3}

= \frac{d}{d x} (n x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= n \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= n \cdot 3 x^{3 - 1}

Simplify

= 3 n x^{2}

x \to 19 lim (\frac{x - 19}{x ^{2} - 361})

\int e^{x} 31 + e^{x} d x

\frac{d y}{d x} = e^{2 x} - 3 y, y (0) = 2

\frac{\partial}{\partial x} (x^{5} + y^{3})

y^{^{''}} + 2 y^{^{'}} + y = 16 e^{- t}

What is the derivative of f(x)=(1n(x^3)) ?
The derivative of f(x)=(1n(x^3)) is 3nx^2
What is the first derivative of f(x)=(1n(x^3)) ?
The first derivative of f(x)=(1n(x^3)) is 3nx^2