What is the sum from n=1 to infinity}((-1)^{n-1 of)/(4n+1) ?

The sum from n=1 to infinity}((-1)^{n-1 of)/(4n+1) is converges

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sum from n=1 to infinity}((-1)^{n-1 of)/(4n+1)

n = 1 \sum \infty \frac{( - 1 ) ^{n - 1}}{4 n + 1}

converges

Solution steps

n = 1 \sum \infty \frac{( - 1 ) ^{n - 1}}{4 n + 1}

Apply Alternating Series Test:

converges

= converges

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What is the sum from n=1 to infinity}((-1)^{n-1 of)/(4n+1) ?
The sum from n=1 to infinity}((-1)^{n-1 of)/(4n+1) is converges