What is the integral from 0 to 3 of 4/(x^2) ?

The integral from 0 to 3 of 4/(x^2) is diverges

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integral from 0 to 3 of 4/(x^2)

\int_{0}^{3} \frac{4}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{3} \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{3}

= 4 [- \frac{1}{x}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

\int 5 x + 2 d x

\frac{d}{d t} (25 - 25 e^{- t} cos (t) - 25 e^{- t} sin (t))

\frac{\partial}{\partial v} (e^{u (v) + v})

\int_{2}^{9} (x^{3} - π x^{2}) d x

f (x) = 8 (e^{x} + e^{x} x), at x = 0

What is the integral from 0 to 3 of 4/(x^2) ?
The integral from 0 to 3 of 4/(x^2) is diverges