What is the limit as x approaches-3+of-(x^2)/(3x+9) ?

The limit as x approaches-3+of-(x^2)/(3x+9) is -infinity

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limit as x approaches-3+of-(x^2)/(3x+9)

x \to - 3 + lim (- \frac{x ^{2}}{3 x + 9})

- \infty

Solution steps

x \to - 3 + lim (- \frac{x ^{2}}{3 x + 9})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to - 3 + lim (\frac{x ^{2}}{3 x + 9})

\frac{x ^{2}}{3 x + 9} = x^{2} \frac{1}{3 x + 9}

= - x \to - 3 + lim (x^{2} \frac{1}{3 x + 9})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= - x \to - 3 + lim (x^{2}) \cdot x \to - 3 + lim (\frac{1}{3 x + 9})

x \to - 3 + lim (x^{2}) = 9

x \to - 3 + lim (\frac{1}{3 x + 9}) = \infty

= - 9 \cdot \infty

Apply Infinity Property:

- c \cdot \infty = - \infty

= - \infty

x \to - 3 + lim (9 - x^{2})

h \to 0 lim (\frac{\frac{2 x + 2 h + 1}{2 - 3 x - 3 h} - \frac{2 x + 1}{2 - 3 x}}{h})

x \to 0 lim (\frac{5}{3 + e ^{\frac{1}{x}}})

x \to - 1 lim (x^{2} - 5 x + 17)

x \to 0 lim (x + \frac{2}{x})

What is the limit as x approaches-3+of-(x^2)/(3x+9) ?
The limit as x approaches-3+of-(x^2)/(3x+9) is -infinity