What is the derivative of (x-1)^4 ?

The derivative of (x-1)^4 is 4(x-1)^3

What is the first derivative of (x-1)^4 ?

The first derivative of (x-1)^4 is 4(x-1)^3

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derivative of

(x - 1)^{4}

4 (x - 1)^{3}

Solution steps

\frac{d}{d x} ((x - 1)^{4})

Apply the chain rule:

4 (x - 1)^{3} \frac{d}{d x} (x - 1)

= 4 (x - 1)^{3} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 4 (x - 1)^{3} \cdot 1

Simplify

= 4 (x - 1)^{3}

\int sec^{4} (x t a) n^{5} x d x

n = 1 \sum \infty \frac{4}{n ( n + 7 )}

n = 2 \sum \infty \frac{n}{n + 2}

f (x) = \frac{x ^{2} + 3 x - 2}{x ^{2} - 5 x + 6}

f (x) = e^{x} - x^{3}

What is the derivative of (x-1)^4 ?
The derivative of (x-1)^4 is 4(x-1)^3
What is the first derivative of (x-1)^4 ?
The first derivative of (x-1)^4 is 4(x-1)^3