What is the derivative of x^2*y ?

The derivative of x^2*y is 2xy+(dy)/(dx)x^2

What is the first derivative of x^2*y ?

The first derivative of x^2*y is 2xy+(dy)/(dx)x^2

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\frac{d}{d x} (x^{2} \cdot y)

2 x y + \frac{d y}{d x} x^{2}

Solution steps

\frac{d}{d x} (x^{2} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = y

= \frac{d}{d x} (x^{2}) y + \frac{d y}{d x} x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= 2 x y + \frac{d y}{d x} x^{2}

\int_{0}^{1} \frac{4}{x ( x + 1 )} d x

y = 4 (x + 1), y = 5 (x + 1), x = 2

\frac{d}{d x} (3 x^{2} y^{2})

\frac{d}{d x} (x (1 - x^{2})^{\frac{1}{2}})

n = 0 \sum \infty i (- 1)^{n}

What is the derivative of x^2*y ?
The derivative of x^2*y is 2xy+(dy)/(dx)x^2
What is the first derivative of x^2*y ?
The first derivative of x^2*y is 2xy+(dy)/(dx)x^2