What is the derivative of f(x)=-1/((x-1)^2) ?

The derivative of f(x)=-1/((x-1)^2) is 2/((x-1)^3)

What is the first derivative of f(x)=-1/((x-1)^2) ?

The first derivative of f(x)=-1/((x-1)^2) is 2/((x-1)^3)

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derivative of

f (x) = - \frac{1}{( x - 1 ) ^{2}}

\frac{2}{( x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{1}{( x - 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{1}{( x - 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d x} ((x - 1)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 1 ) ^{3}} \frac{d}{d x} (x - 1)

= - \frac{2}{( x - 1 ) ^{3}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= - (- \frac{2}{( x - 1 ) ^{3}} \cdot 1)

Simplify

= \frac{2}{( x - 1 ) ^{3}}

(1 - x^{2}) y^{^{''}} + 2 x y^{^{'}} = 0

\int \frac{x}{7 x - 6} d x

\frac{d}{d x} (1 - x^{4})

6 y^{^{''}} + y^{^{'}} - 2 y = 0

\frac{d ^{2}}{d x ^{2}} (e^{- k x^{2}})

What is the derivative of f(x)=-1/((x-1)^2) ?
The derivative of f(x)=-1/((x-1)^2) is 2/((x-1)^3)
What is the first derivative of f(x)=-1/((x-1)^2) ?
The first derivative of f(x)=-1/((x-1)^2) is 2/((x-1)^3)