What is the integral of (-8sec(x)tan(x)-3sec^2(x)) ?

The integral of (-8sec(x)tan(x)-3sec^2(x)) is -8sec(x)-3tan(x)+C

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integral of (-8sec(x)tan(x)-3sec^2(x))

\int (- 8 sec (x) tan (x) - 3 sec^{2} (x)) d x

- 8 sec (x) - 3 tan (x) + C

Solution steps

\int - 8 sec (x) tan (x) - 3 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 8 sec (x) tan (x) d x - \int 3 sec^{2} (x) d x

\int 8 sec (x) tan (x) d x = 8 sec (x)

\int 3 sec^{2} (x) d x = 3 tan (x)

= - 8 sec (x) - 3 tan (x)

Add a constant to the solution

= - 8 sec (x) - 3 tan (x) + C

y^{^{''}} + 5 y^{^{'}} - 6 y = (3 x - 1) e^{x}

e^{x^{4}}

x + y = 7

\frac{d}{d x} (x^{c})

\frac{d}{d x} (3 x^{\frac{4}{3}} - \frac{3 x ^{\frac{2}{3}}}{32})

What is the integral of (-8sec(x)tan(x)-3sec^2(x)) ?
The integral of (-8sec(x)tan(x)-3sec^2(x)) is -8sec(x)-3tan(x)+C