What is the derivative of 3x^{4/3}-(3x^{2/3}/(32)) ?

The derivative of 3x^{4/3}-(3x^{2/3}/(32)) is (-1+64x^{2/3})/(16x^{1/3)}

What is the first derivative of 3x^{4/3}-(3x^{2/3}/(32)) ?

The first derivative of 3x^{4/3}-(3x^{2/3}/(32)) is (-1+64x^{2/3})/(16x^{1/3)}

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\frac{d}{d x} (3 x^{\frac{4}{3}} - \frac{3 x ^{\frac{2}{3}}}{32})

\frac{- 1 + 64 x ^{\frac{2}{3}}}{16 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (3 x^{\frac{4}{3}} - \frac{3 x ^{\frac{2}{3}}}{32})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{\frac{4}{3}}) - \frac{d}{d x} (\frac{3 x ^{\frac{2}{3}}}{32})

\frac{d}{d x} (3 x^{\frac{4}{3}}) = 4 x^{\frac{1}{3}}

\frac{d}{d x} (\frac{3 x ^{\frac{2}{3}}}{32}) = \frac{1}{16 x ^{\frac{1}{3}}}

= 4 x^{\frac{1}{3}} - \frac{1}{16 x ^{\frac{1}{3}}}

Simplify

4 x^{\frac{1}{3}} - \frac{1}{16 x ^{\frac{1}{3}}} : \frac{- 1 + 64 x ^{\frac{2}{3}}}{16 x ^{\frac{1}{3}}}

= \frac{- 1 + 64 x ^{\frac{2}{3}}}{16 x ^{\frac{1}{3}}}

\int t^{2} cos^{2} (t) d t

\int \frac{x + 10}{2 - x - 3 x ^{2}} d x

\frac{d}{d x} (3 x^{2} - 9)

n = 0 \sum \infty \frac{4 ^{n}}{5 ^{n}}

f (x) = (3 x + 70)^{50}

What is the derivative of 3x^{4/3}-(3x^{2/3}/(32)) ?
The derivative of 3x^{4/3}-(3x^{2/3}/(32)) is (-1+64x^{2/3})/(16x^{1/3)}
What is the first derivative of 3x^{4/3}-(3x^{2/3}/(32)) ?
The first derivative of 3x^{4/3}-(3x^{2/3}/(32)) is (-1+64x^{2/3})/(16x^{1/3)}