What is (\partial)/(\partial x)(10^{x^2+x}) ?

The answer to (\partial)/(\partial x)(10^{x^2+x}) is ln(10)*10^{x^2+x}(2x+1)

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(\partial)/(\partial x)(10^{x^2+x})

\frac{\partial}{\partial x} (1 0^{x^{2} + x})

ln (10) \cdot 1 0^{x^{2} + x} (2 x + 1)

Solution steps

\frac{\partial}{\partial x} (1 0^{x^{2} + x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

1 0^{x^{2} + x} = e^{(x^{2} + x) l n (10)}

= \frac{\partial}{\partial x} (e^{(x^{2} + x) l n (10)})

Apply the chain rule:

e^{(x^{2} + x) l n (10)} \frac{\partial}{\partial x} ((x^{2} + x) ln (10))

= e^{(x^{2} + x) l n (10)} \frac{\partial}{\partial x} ((x^{2} + x) ln (10))

\frac{\partial}{\partial x} ((x^{2} + x) ln (10)) = ln (10) (2 x + 1)

= e^{(x^{2} + x) l n (10)} ln (10) (2 x + 1)

e^{(x^{2} + x) l n (10)} = 1 0^{x^{2} + x}

= ln (10) \cdot 1 0^{x^{2} + x} (2 x + 1)

y = \frac{4}{x}

\int_{2}^{8} \frac{1}{x ^{2} - 1} d x

\frac{d}{d x} (\frac{1}{2 x + 3})

x^{2} \cdot cos (x)

\frac{d}{d x} (\frac{x ^{3}}{3} - \frac{1}{4 x})

What is (\partial)/(\partial x)(10^{x^2+x}) ?
The answer to (\partial)/(\partial x)(10^{x^2+x}) is ln(10)*10^{x^2+x}(2x+1)