What is the derivative of 6x+2ln(x)-400 ?

The derivative of 6x+2ln(x)-400 is 2/x+6

What is the first derivative of 6x+2ln(x)-400 ?

The first derivative of 6x+2ln(x)-400 is 2/x+6

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derivative of

6 x + 2 ln (x) - 400

\frac{2}{x} + 6

Solution steps

\frac{d}{d x} (6 x + 2 ln (x) - 400)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) + \frac{d}{d x} (2 ln (x)) - \frac{d}{d x} (400)

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

\frac{d}{d x} (400) = 0

= 6 + \frac{2}{x} - 0

Simplify

= \frac{2}{x} + 6

\frac{lo g _{10} ( 1 )}{x}

\frac{1}{x ^{n}}

1 3^{t}

(\frac{1}{x})^{x}

e^{1} - x

What is the derivative of 6x+2ln(x)-400 ?
The derivative of 6x+2ln(x)-400 is 2/x+6
What is the first derivative of 6x+2ln(x)-400 ?
The first derivative of 6x+2ln(x)-400 is 2/x+6