What is the first derivative of e^1-x ?

The first derivative of e^1-x is -1

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derivative of e^1-x

derivative of

e^{1} - x

- 1

Solution steps

\frac{d}{d x} (e^{1} - x)

Simplify

e^{1} - x : e - x

= \frac{d}{d x} (e - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d e}{d x} - \frac{d x}{d x}

\frac{d e}{d x} = 0

\frac{d x}{d x} = 1

= 0 - 1

Simplify

= - 1

\frac{( 2 x + 3 )}{( x ^{3} - 5 )}

4 cos (4 x^{2})

\frac{d}{d t} (\frac{( sin ( t ) )}{( 1 - cos ( t ) )})

e^{3} x

(x^{2} + 1) e^{x}