What is the first derivative of e^3x ?

The first derivative of e^3x is e^3

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derivative of e^3x

derivative of

e^{3} x

e^{3}

Solution steps

\frac{d}{d x} (e^{3} x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{3} \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= e^{3} \cdot 1

Simplify

= e^{3}

(x^{2} + 1) e^{x}

\frac{d}{d t} (- 2 + 5 t)

x^{s i n^{2} (x)}

\frac{d}{df} (\frac{( f ( 1 ) + f ( 4 ) )}{( - 3 f ( 0 ) )})

e^{x^{2} + y^{2}}