What is the derivative of (x^{1/2}-1)/(x^{1/2)} ?

The derivative of (x^{1/2}-1)/(x^{1/2)} is 1/(2x^{3/2)}

What is the first derivative of (x^{1/2}-1)/(x^{1/2)} ?

The first derivative of (x^{1/2}-1)/(x^{1/2)} is 1/(2x^{3/2)}

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derivative of

\frac{x ^{\frac{1}{2}} - 1}{x ^{\frac{1}{2}}}

\frac{1}{2 x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{x ^{\frac{1}{2}} - 1}{x ^{\frac{1}{2}}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{\frac{1}{2}} - 1 ) x ^{\frac{1}{2}} - \frac{d}{d x} ( x ^{\frac{1}{2}} ) ( x ^{\frac{1}{2}} - 1 )}{( x ^{\frac{1}{2}} ) ^{2}}

\frac{d}{d x} (x^{\frac{1}{2}} - 1) = \frac{1}{2 x ^{\frac{1}{2}}}

\frac{d}{d x} (x^{\frac{1}{2}}) = \frac{1}{2 x ^{\frac{1}{2}}}

= \frac{\frac{1}{2 x ^{\frac{1}{2}}} x ^{\frac{1}{2}} - \frac{1}{2 x ^{\frac{1}{2}}} ( x ^{\frac{1}{2}} - 1 )}{( x ^{\frac{1}{2}} ) ^{2}}

Simplify

\frac{\frac{1}{2 x ^{\frac{1}{2}}} x ^{\frac{1}{2}} - \frac{1}{2 x ^{\frac{1}{2}}} ( x ^{\frac{1}{2}} - 1 )}{( x ^{\frac{1}{2}} ) ^{2}} : \frac{1}{2 x ^{\frac{3}{2}}}

= \frac{1}{2 x ^{\frac{3}{2}}}

1 + ln (x)

7 x^{5} + 17

x^{3} - 3 x - 5

\frac{x ^{2}}{tan ( x )}

y = 4 cos (4 x^{2})

What is the derivative of (x^{1/2}-1)/(x^{1/2)} ?
The derivative of (x^{1/2}-1)/(x^{1/2)} is 1/(2x^{3/2)}
What is the first derivative of (x^{1/2}-1)/(x^{1/2)} ?
The first derivative of (x^{1/2}-1)/(x^{1/2)} is 1/(2x^{3/2)}