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Popular >

y^'=x^2y-y+x^2-1

Solution

y^{^{'}} = x^{2} y - y + x^{2} - 1

Solution

y = e^{\frac{x ^{3}}{3} - x + c_{1}} - 1

Solution steps

y^{'} (x) = x^{2} y - y + x^{2} - 1

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} - x + c_{1}} - 1

y = e^{\frac{x ^{3}}{3} - x + c_{1}} - 1

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x \to 4 lim (\frac{x}{- 7 x + 1})

(\partial)/(\partial x)(x^2ln(xy))

\frac{\partial}{\partial x} (x^{2} ln (x y))

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2y-y+x^2-1 ?
The solution for y^'=x^2y-y+x^2-1 is y=e^{(x^3)/3-x+c_{1}}-1