What is the d/(d{x)}({x}+2{y}+3{z}) ?

The d/(d{x)}({x}+2{y}+3{z}) is 1

What is the first d/(d{x)}({x}+2{y}+3{z}) ?

The first d/(d{x)}({x}+2{y}+3{z}) is 1

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\frac{d}{d x} (x + 2 y + 3 z)

1

Solution steps

\frac{d}{d x} (x + 2 y + 3 z)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (2 y) + \frac{d}{d x} (3 z)

\frac{d}{d x} (x) = 1

\frac{d}{d x} (2 y) = 0

\frac{d}{d x} (3 z) = 0

= 1 + 0 + 0

Simplify

= 1

y^{3} (x^{2} + 2)

y = 5^{9 x - 5}

1 + cos (x)

(5 x^{2} + 3)^{4}

e^{5} x

What is the d/(d{x)}({x}+2{y}+3{z}) ?
The d/(d{x)}({x}+2{y}+3{z}) is 1
What is the first d/(d{x)}({x}+2{y}+3{z}) ?
The first d/(d{x)}({x}+2{y}+3{z}) is 1