What is the derivative of 1+cos(x) ?

The derivative of 1+cos(x) is -sin(x)

What is the first derivative of 1+cos(x) ?

The first derivative of 1+cos(x) is -sin(x)

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derivative of

1 + cos (x)

- sin (x)

Solution steps

\frac{d}{d x} (1 + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (x)) = - sin (x)

= 0 - sin (x)

Simplify

= - sin (x)

(5 x^{2} + 3)^{4}

e^{5} x

6 x^{2} + 5

\frac{x + 3}{x}

\frac{( x + 1 )}{x}

What is the derivative of 1+cos(x) ?
The derivative of 1+cos(x) is -sin(x)
What is the first derivative of 1+cos(x) ?
The first derivative of 1+cos(x) is -sin(x)