What is the derivative of y=x^2+7 ?

The derivative of y=x^2+7 is 2x

What is the first derivative of y=x^2+7 ?

The first derivative of y=x^2+7 is 2x

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derivative of

y = x^{2} + 7

2 x

Solution steps

\frac{d}{d x} (x^{2} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7) = 0

= 2 x + 0

Simplify

= 2 x

2 sin (2 + 3 x^{2})

5 x^{7} + 6 x^{4} - 2

\frac{y ^{2}}{2}

2 x^{6} (1 + x)^{5}

t^{- 1}