What is the first derivative of (y^2)/2 ?

The first derivative of (y^2)/2 is y

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derivative of (y^2)/2

derivative of

\frac{y ^{2}}{2}

y

Solution steps

\frac{d}{d y} (\frac{y ^{2}}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} \cdot 2 y^{2 - 1}

Simplify

\frac{1}{2} \cdot 2 y^{2 - 1} : y

= y

2 x^{6} (1 + x)^{5}

t^{- 1}

\frac{x ^{3} + x - 1}{2}

e^{x} + 2

ln (x^{- 1})