What is the first derivative of e^x+2 ?

The first derivative of e^x+2 is e^x

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derivative of e^x+2

derivative of

e^{x} + 2

e^{x}

Solution steps

\frac{d}{d x} (e^{x} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (2)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2) = 0

= e^{x} + 0

Simplify

= e^{x}

ln (x^{- 1})

(x^{2} + 3 x)^{4}

\frac{cos ( x ) + 1}{x}

\frac{x ^{2}}{( e ^{x} - 1 )}

2 cos (2 x - 1)