What is the derivative of ((x^2-x+1))/((a^3-3)) ?

The derivative of ((x^2-x+1))/((a^3-3)) is (2x-1)/(a^3-3)

What is the first derivative of ((x^2-x+1))/((a^3-3)) ?

The first derivative of ((x^2-x+1))/((a^3-3)) is (2x-1)/(a^3-3)

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derivative of

\frac{( x ^{2} - x + 1 )}{( a ^{3} - 3 )}

\frac{2 x - 1}{a ^{3} - 3}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - x + 1}{a ^{3} - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{a ^{3} - 3} \frac{d}{d x} (x^{2} - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{a ^{3} - 3} (\frac{d}{d x} (x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (1))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{1}{a ^{3} - 3} (2 x - 1 + 0)

Simplify

\frac{1}{a ^{3} - 3} (2 x - 1 + 0) : \frac{2 x - 1}{a ^{3} - 3}

= \frac{2 x - 1}{a ^{3} - 3}

\frac{d}{d t} (a^{2} t)

(3^{x})^{2}

\frac{d}{d s} (3 s)

[f (x)]^{2}

x tan (3 x^{2} + 4 x + 1)

What is the derivative of ((x^2-x+1))/((a^3-3)) ?
The derivative of ((x^2-x+1))/((a^3-3)) is (2x-1)/(a^3-3)
What is the first derivative of ((x^2-x+1))/((a^3-3)) ?
The first derivative of ((x^2-x+1))/((a^3-3)) is (2x-1)/(a^3-3)